(5)/(x^2+27x+1)

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Solution for (5)/(x^2+27x+1) equation:


D( x )

x^2+27*x+1 = 0

x^2+27*x+1 = 0

x^2+27*x+1 = 0

x^2+27*x+1 = 0

DELTA = 27^2-(1*1*4)

DELTA = 725

DELTA > 0

x = (725^(1/2)-27)/(1*2) or x = (-725^(1/2)-27)/(1*2)

x = (5*29^(1/2)-27)/2 or x = (-5*29^(1/2)-27)/2

x in (-oo:(-5*29^(1/2)-27)/2) U ((-5*29^(1/2)-27)/2:(5*29^(1/2)-27)/2) U ((5*29^(1/2)-27)/2:+oo)

5/(x^2+27*x+1) = 0

x^2+27*x+1 = 0

x^2+27*x+1 = 0

DELTA = 27^2-(1*1*4)

DELTA = 725

DELTA > 0

x = (725^(1/2)-27)/(1*2) or x = (-725^(1/2)-27)/(1*2)

x = (5*29^(1/2)-27)/2 or x = (-5*29^(1/2)-27)/2

(x-((-5*29^(1/2)-27)/2))*(x-((5*29^(1/2)-27)/2)) = 0

5/((x-((-5*29^(1/2)-27)/2))*(x-((5*29^(1/2)-27)/2))) = 0

x belongs to the empty set

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